Validate Armstrong Number using java- Interview qus Selenium

Check if a number is Armstrong or not.

Definition:  A number is armstrong if the sum of the cubes of digit of number is equal to the number.
ex- 407 = 4*4*4 + 0*0*0 + 7*7*7

import java.util.Scanner; public class ArmstrongNum{ public static void main(String[] args){ Scanner in = new Scanner(System.in); System.out.println("Enter a number which you want to check whether that is armstrong or not: "); int n = in.nextInt(); int a = n, c=0, b=0; while(a!=0){ c = a%10; a = a/10; b = b + c*c*c; } if(b==n){ System.out.println("Number:   "+n+" is an armstrong number."); }else{ System.out.println("Number "+n+" is not an armstrong number."); } } }

Output

Enter a number which you want to check whether that is armstrong or not: 407 Number: 407 is an armstrong number.

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