EvenOdd function in Java for selenium Interview

Verify a number is Even or Odd

import java.util.Scanner; public class EvenorOdd{ public static void main(String[] args){ Scanner in = new Scanner(System.in); System.out.println("Enter a number which you want to check whether is even or odd"); int n = in.nextInt(); if(n%2==0){ System.out.println(n+" is an even number."); }else{ System.out.println(n+" is an odd number.");  } } }

Expected Output

1 2 3

Enter a number which you want to check whether  is even or odd  4  4 is an even number.

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